Hydration is the key to healthy living. We all know the importance of hydration to our wellness. And especially in summer, there is fluid loss from the body when the temperature goes high. In this…
Today we are solving separable or homogeneous first order equation.
In the equations
A(x) + B(y) dy/dx = 0
or A(x) dx + B(y) dy = 0
we have separated the variables
Integrate both sides
( integral of A(x) dx ) + ( integral of B(y) dy ) = C
Example 1: 2x dx + ( — 1 / (y² + 1) ) dy = 0
x² — arc tan (y) = C
y = tan( x² — C)
Homogeneous first order equation:
dy/dx = F(y/x)
Let y = v x
dy/dx = v + x dv/dx = F(v)
so dx/ x + dv / ( v — F(v) ) = 0 is now separable equation
Example 2: dy/dx = — ( x² + y² ) / (2 x y) = — ( 1 + (y/x)² ) / (2 (y/x))
v = y / x , F(v) = — (1 + v²) /(2 v)
v — F(v) = v + ( 1 + v²) / (2 v) = ( 1 + 3 v²) / (2 v)
dx / x + 2 v dv / (1 + 3 v²) = 0
ln |x| + (1/3) ln (1 + 3 v²) = C
x³ ( 1 + 3 v²) = + or — e^(3C) = C1
x³ (1 + 3 y² / x² ) = C1
x³ + 3 x y² = C1
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